![]() The shear and moment curves can be obtained by successive integration of the \(q(x)\) distribution, as illustrated in the following example. The bending moment diagram indicates the bending. Hence the value of the shear curve at any axial location along the beam is equal to the negative of the slope of the moment curve at that point, and the value of the moment curve at any point is equal to the negative of the area under the shear curve up to that point. The shear force diagram indicates the shear force withstood by the beam section along the length of the beam. A moment balance around the center of the increment givesĪs the increment \(dx\) is reduced to the limit, the term containing the higher-order differential \(dV\ dx\) vanishes in comparison with the others, leaving ![]() The distributed load \(q(x)\) can be taken as constant over the small interval, so the force balance is: C200 KN D200KN E90KN Distance between C to. Another way of developing this is to consider a free body balance on a small increment of length \(dx\) over which the shear and moment changes from \(V\) and \(M\) to \(V dV\) and \(M dM\) (see Figure 8). Shear
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